the mass of the resulting strontium fluoride precipitate is 2.27m.
What is mass?
mass is quantitative measure of inertia,a fundamental property of all matter.
Sr(NO3)2(aq) + 2NaF(aq) ==> SrF2(s) + 2NaNO3 ... balanced equation
moles Sr(NO3)2 = 0.180 L x 2.400 mol/L = 0.432 moles
moles NaF = 0.200 L x 3.088 mol/L = 0.6176 moles
NaF is LIMITING REACTANT b/c it takes 2 NaF per 1 Sr(NO3)2 and there isn't enough NaF.
Mass of Sr(NO3)2 precipitate = 0.6176 mol NaF x 1 mol SrF2 / 2 mol NaF x 125.6 g SrF2/mol = 38.8 g
Final volume = 180 ml + 200 ml = 380 ml = 0.380 L
[F-] = 0 since all the F- is precipitated as SrF2
[Sr2+] = 0.432 mol - 0.309 mol = 0.123 mol/0.380 L = 0.324 M
[Na+] = 0.6176 moles / 0.380 L = 1.63 M
[NO3-] = 0.432 moles x 2 = 0.864 mol/0.380 L = 2.27 M
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