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Joan has a collection of quarters and nickels worth $2.50. There are 14 more nickels than quarters. How many coins of each type does Joan have?

Respuesta :

Answer: 20 nickels and 6 quarters.

Step-by-step explanation:

           Let q be equal to quarters and n be equal to nickels. We will write a system of equations to help us solve.

      First, we know each quarter is $0.25 and each nickel is $0.05.

0.25q + 0.05n = 2.5

      Next, we know there are 14 more nickels than quarters.

n = q + 14

      We will plug the second equation into the first and solve.

0.25q + 0.05n = 2.5

0.25q + 0.05(q + 14) = 2.5

0.25q + 0.05q + 0.7 = 2.5

0.3q = 1.8

q = 6

      Joan has 6 quarters. We know he has 14 more nickels than quarters, so we will use addition.

6 + 14 = 20 nickels

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