Question

Determine the magnitude and direction of the force between two parallel wires 35 m long and 7.0 cm apart, each carrying 35 A in the same direction. O The force on each wire will be attractive. O The force on each wire will be repulsive. O The wires will not interact.

Answer 1

3.5*10^-5 N/m  is the magnitude of the force between two parallel wires 35 m long and 7.0 cm apart, each carrying 35 A current and the force on each wire will be repulsive.

What is Magnitude of force means?

The number which shows or represents the strength  of the force is termed as the magnitude of that force.

Data given :

Two parallel wires

35 m long and 7.0 cm apart,

each carrying 35 A  current .

To find the magnitude and direction of current.

f=μ/4π*2$I_{1}$$I_{2}$/d

f=$10^{-7}$*2*35*35/7

f=3.5*10^-5

​Hence, 3.5*10^-5 N is the magnitude of the force between two parallel wires 35 m long and 7.0 cm apart, each carrying 35 A current.

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