Jar A contains 4 red marbles and 6 blue marbles. Jar B contains 8 red marbles and 2 blue marbles. (20 points) (a) How many ways are there to choose a marble from Jar A or Jar B? (b) How many ways are there to choose a marble from Jar A and Jar B? (C) How many ways are there to choose a red marble from Jar A and Jar B? (d) If you choose marbles from Jar A and Jar B at random, what is the probability that they are both red?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true.

An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

So, the probability that both marbles will be red is:

Probability formula: P(E) = Favourable events/Total events

We know that:

Jar A: 4 red marbles and 6 blue marbles

The probability of randomly choosing red marble is:

P(E) = Favourable events/Total events

P(E) = 4/10

P(E) = 2/5

Jar B: 8 red marbles and 2 blue marbles

The probability of randomly choosing red marble is:

P(E) = Favourable events/Total events

P(E) = 8/10

P(E) = 4/5

So, the total probability will be:

2/5 * 4/5

8/25

Therefore, the probability of randomly getting the red marbles from both Jar A and Jar B is 8/25.

Know more about the probability here:

https://brainly.com/question/29523308

#SPJ4

Correct question:

Jar A contains 4 red marbles and 6 blue marbles. Jar B contains 8 red marbles and 2 blue marbles. (20 points) If you choose marbles from Jar A and Jar B at random, what is the probability that they are both red?