Answer:
x = 7
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Vertex form of a quadratic equation}\\\\$y=a(x-h)^2+k$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the vertex. \\ \phantom{ww}$\bullet$ $a$ is some constant.\\\end{minipage}}[/tex]
Given equation:
[tex]y=-2(x-7)^2+11[/tex]
The given equation is in vertex form.
The axis of symmetry of a parabola with a vertical axis of symmetry is:
where h is the x-value of the vertex.
As the vertex of the given equation is (7, 11), the axis of symmetry is: