What is the equation of the line of symmetry for the parabola represented by the equation y=−2(x−7^)2+11?

Enter your answer as the correct equation, like this: x = 42

[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Vertex form of a quadratic equation}\\\\$y=a(x-h)^2+k$\\\\where:\\ \phantom{ww}$\bullet$ $(h,k)$ is the vertex. \\ \phantom{ww}$\bullet$ $a$ is some constant.\\\end{minipage}}[/tex]

Given equation:

[tex]y=-2(x-7)^2+11[/tex]

The given equation is in vertex form.

The axis of symmetry of a parabola with a vertical axis of symmetry is:

x = h

where h is the x-value of the vertex.

As the vertex of the given equation is (7, 11), the axis of symmetry is:

x = 7

What is the equation of the line of symmetry for the parabola represented by the equation y=−2(x−7^)2+11? Enter your answer as the correct equation, like this: x = 42

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What is the equation of the line of symmetry for the parabola represented by the equation y=−2(x−7^)2+11?

Enter your answer as the correct equation, like this: x = 42