Respuesta :

Answer:

[tex]f^{-1}(x)=\frac{1-2x}{x-1}[/tex]

Step-by-step explanation:

1. replace f(x) with x, and x with y:  [tex]f(x)=\frac{x+1}{x+2} == > x=\frac{y+1}{y+2}[/tex]

2. Solve for y:

   [tex]x=\frac{y+1}{y+2}[/tex]

   [tex]x(y+2)=y+1[/tex]

   [tex]xy+2x=y+1[/tex]

   [tex]xy-y=1-2x[/tex]

   [tex]y(x-1)=1-2x[/tex]

   [tex]y=\frac{1-2x}{x-1}[/tex]

3. Replace y with f⁻¹(x)

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