Find the inverse of f(x)=(x+1)(x+2). Show your work how to get the answer.

Answer:
[tex]f^{-1}(x)=\frac{1-2x}{x-1}[/tex]
Step-by-step explanation:
1. replace f(x) with x, and x with y: [tex]f(x)=\frac{x+1}{x+2} == > x=\frac{y+1}{y+2}[/tex]
2. Solve for y:
[tex]x=\frac{y+1}{y+2}[/tex]
[tex]x(y+2)=y+1[/tex]
[tex]xy+2x=y+1[/tex]
[tex]xy-y=1-2x[/tex]
[tex]y(x-1)=1-2x[/tex]
[tex]y=\frac{1-2x}{x-1}[/tex]
3. Replace y with f⁻¹(x)