Question

A bowl has only red, green, and purple grapes. The probability of picking a red grape out of the bowl, eating it, and then picking a green grape out of the bowl is 1/8 The probability of picking just a red grape is 1/4 . What is the probability of picking a green grape?

Answer 1

Answer:

$\rm P(green)=\dfrac{1}{2}$

Step-by-step explanation:

Given probabilities:

• $\rm P(red)=\dfrac{1}{4}$

• $\rm P(red)\; and \; P(green)=\dfrac{1}{8}$

Therefore, according the the multiplication rule of probability:

$\begin{aligned}\rm P(red) \times P(green)&=\dfrac{1}{8}\\\\\implies \rm \dfrac{1}{4} \times P(green)&=\dfrac{1}{8}\\\\ \implies \rm P(green)&=\dfrac{1}{8} \div \dfrac{1}{4} \\\\ \impies \rm P(green_&=\dfrac{1}{8} \times \dfrac{4}{1}\\\\\implies \rm P(green)&=\dfrac{4}{8}=\dfrac{1}{2}\end{aligned}$