Question

You are pushing your nephew on a playground swing. The swing seat is suspended from a horizontal bar by two light chains. Assume that the estimation of the length of each chain is 2. 0 m. Treat the motion of the child as that of a simple pendulum and assume that for safety the amplitude of the motion is kept small. You give your nephew a light push each time he reaches his closest distance from you.


Required:

How much time elapses between your pushes?

Answer 1

The time that elapses between the pushes is 2.84 seconds. This is solved using the time period of a simple pendulum.

What is the time period of a simple pendulum?

The time it takes to complete one oscillation is known as the pendulum's time period. The following is the formula:

T = 2π√(L/g)

Where:

t = Time

L = length of pendulum = 2.0m

g = acceleration due to gravity = 9.8m/s²

Hence:

T = 2 x 3.14 x √(2/9.8)

T = 6.28 x √0.2040816326530612

T = 6.28 x 0.45175395145

T = 2.83701481511

T $\approx$ 2.84 seconds.

Learn more about simple pendulums:
https://brainly.com/question/14759840
#SPJ1