Question

The water potential of the root tissue of a plant has been found to be -5. 4 bars. If you place this root tissue in a 0. 4M sucrose solution at 22 C in an open beaker, what is the water potential of the solution? which direction will the net flow of water be? Find your answers in bars and box your answers

Answer 1

The water will move from high water potential area inside the root tissue to low water potential area inside the beaker.

solute potential ψs = -CRT

Solute potential  = (-1) (0.4) (0.0831)(273+22)

ψs = - 9.8058 ≈ - 10 bars

water potential = solute potential + pressure potential

Water potential ψ = ψs + ψp

ψ = - 10 bars + 0 bars = -10 bars

Since water moves area of high water potential to area of low water potential and the water pontential in beaker is -10 bars which is lower than that of root tissue. Thus water will moves root from root tissue to beaker.

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