Question

An object of mass 10kg is moving with an initial velocity of 10m/s at a ground level. As it moves up a frictionless ramp , it’s velocity decreases to 3m/s. At what height is the velocity 3m/s?

Answer 1

The height of the object is 4.64 m when the velocity of the object is 3m/s.

What is the equation of motion?

The equations of motion set up the relationship between the velocity, acceleration, time, and displacement of a moving body.

The equations of motions can be mathematically represented as:

$v = u +at\\S = ut +\frac{1}{2}at^2\\ v^2-u^2= 2aS$

Given, the initial velocity of the object, u = 10 m/s

The final velocity of the object, u = 3 m/s

The object moves in an upward direction, g = -9.8 m/s²

From the equation of motion, find time:  $v = u -gt$

3 = 10 - 9.8 ×t

9.8 t = 10 - 3 = 7

t = 0.714 s

From the 2nd equation of motion, calculate height when the velocity is 3m/s.

h = u×t + (1/2)g×t²

h = 10× 0.714 - (1/2)× 9.8×(0.714)²

h = 7.14 - 2.498

h = 4.64 m

Learn more about the equation of motion, here:

brainly.com/question/16982759

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