We are given with the mass % of acetic acid, which means in a sample of 100 g, 5 g is of acetic acid.
also, given that is density of vinegar, acetic acid is 1.01 g/l
and are asked to determine the molarity of acetic acid.
Molarity = number of moles/volume
number of moles of acetic acid = Given Mass/Molar Mass
Molar Mass of acetic acid = 60 g/mol
number of moles = 5/60
number of moles = 0.083 moles
For volume, we know that density = mass/volume
volume = mass/density
volume of acetic acid = 5/1.01
volume = 4.95 l
Molarity = number of moles/volume
Molarity of acetic acid = 0.083/4.95
Molarity = 0.0167M
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