Respuesta :
Answer: D) -2.04 x [tex]10^{-18}[/tex] , Emission
Explanation:
Use Bohr's equation for energy produced from a change in orbital levels.[tex]-2.178*10^{-18} (\frac{1^{2}}{n_{final}^{2} } - \frac{1^{2} }{n_{initial} ^{2} } )[/tex][tex]=E[/tex]
Substitute and you will get your answer!
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