The balanced net ionic equation for the reaction between potassium sulfide and lead(II) nitrate is Pb²⁺(aq) + S²⁻(aq) → PbS(s)
Writing balanced net ionic equation for a reaction
From the question, we are to write the balanced net ionic equation for the given chemical reaction.
The given chemical reaction is
K₂S(aq) + Pb(NO₃)₂(aq) →
The between potassium sulfide and lead(II) nitrate will produce potassium nitrate and lead sulfide.
That is,
K₂S(aq) + Pb(NO₃)₂(aq) → KNO₃(aq) + PbS(s)
Now, balance the equation
K₂S(aq) + Pb(NO₃)₂(aq) → 2KNO₃(aq) + PbS(s)
Write the complete ionic equation
2K⁺(aq) + S²⁻(aq) + Pb²⁺(aq) + 2NO₃⁻(aq) → 2K⁺(aq) + 2NO₃⁻(aq) + PbS(s)
Cancel out the spectator ions
S²⁻(aq) + Pb²⁺(aq) → + PbS(s)
Hence, the balanced net ionic equation is
Pb²⁺(aq) + S²⁻(aq) → PbS(s)
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