Question

For each set of dilutions (bleach and mouthwash), the first tube contained a 1:11 dilution (0. 5 mL of agent was added to 5. 0 mL of nutrient broth). What dilution was the tube where the more effective of the two agents inhibited growth? Hint: You will have to calculate the dilution of each tube 2 – 4

Answer 1

Each tube's dilution is as follows:

Tube 2; 8.26 × 10-³

Tube 3; 7.5 × 10-⁴

Tube 4; 6.83 × 10-⁵

Each time a dilution gets diluted even more;

In other words, 0.5 mL of agent was added to 5.0 mL of nutritional broth, giving a dilution ratio of 1: 11.

The dilution factor for the first tube is 1: 11 = 9.1 10-2.

The second tube was created by mixing 0.5 mL of the first tube with 5.0 mL of the nutritional broth. This results in a dilution factor of (1/11) (1/11) = 1/121 = 8.26 10-3.

The third tube's dilution factor is (1/11) (1/11) (1/11) = 1/121 = 7.5 10-4 because 0.5 mL of the second tube was added to 5.0 mL of the nutritional broth.

The dilution factor is then (1/11) (1/11) (1/11) = 1/14641 = 6.83 10-5 for the fourth tube, which contained 0.5mL of the third tube and 5.0mL of the nutritional broth.

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