a 2 kg mass hangs motionless from a partially stretched spring having a spring constant of 177 n/m. what is the magnitude of the force (in n) that would be required to pull the mass down by an additional 7 cm? never include units with your answer.

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For a 2 kg mass to hang motionless from a partially stretched spring with a spring constant, a force of 8.608 N would need to be applied in order to pull the mass down an additional 7 cm.

A scalar is used to indicate a force's magnitude, which is the amount to which the body it is acting on will be accelerated by the force (a single number). The force's strength can also be considered in terms of its magnitude. When forces are shown as vectors, the force's magnitude is typically explicitly labeled.

m=2 kg and  spring constant,=177 N/m

The extension should be x.

F =  spring constant, x x = mg / K = 2 x 9.8 / 177 = 0.1107 m at this time, d = 7 cm = 0.07 m

F represents additional force.

(mg + F) = K (x + d), where (2 x 9.8 + F) = 177(0.110 + 0.07)

19.6 + F = 31.86\sF = 12.26 N

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