The empirical formula of metal fluoride is CuF2 when a 12.68 g sample of copper is heated in the presence of excess fluorine a metal fluoride is formed with a mass of 20.27g.
Empirical formula of the compound is the Ratio of the atoms present in the compound .It is a simplest whole number chemical compound.
No. of moles of the element is calculated as ,
No of moles of the element= mass of the element / molar mass of the element
so mass of the copper is 12.68gram and the molar mass of the carbon is 63.546 g/mole. It forms the total mass of 0.1995 mol. Reacting with flourine to get CuF2 .
Mass of the metal fluoride formed is 20.27 g.
Moles of copper = 12.68g/63.546g/mole
molar mass of florine is 18.99 g/mol.
molar mass of CuF2 is 101.543 g/mol.
so, 0.1995 mol . 101.543 g/mole = 20.27 g
hence proved the empirical formula of metal fluoride is CuF2.
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