Question

a 0.764-g sample containing barium ions is completely dissolve in water and treated with excess na2so4. 0.843 g of baso4 precipitate. what is the mass percent of barium in the sample?

Answer 1

51.9% is the mass percent of barium in the sample

The molar mass of BaSO₄ =  233.3 g/mol

Barium molecular weight = 137.3 g/mol

%Ba in BaSO₄ = 137.3/233.3 × 100 = 58.5%

i.e; the mass of Ba²⁺ ions in 0.764 g of BaSO₄

58.85% of 0.764 = 0.439 g

% of Ba²⁺ ions in the sample = 0.439/0.846 × 100 = 51.9%

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