At 1 atm pressure the heat of sublimation of gallium is 277 kJ/mol and the heat of vaporization is 271 kJ/mol. heat is required to melt 0.500 mol of gallium at 1.00 atm pressure is 3 kJ.
The data given as follows :
The heat of sublimation of gallium = 277 kJ/mol
The heat of vaporization = 271 kJ/mol
The difference between the heat of sublimation of gallium and the heat of vaporization is given as :
ΔH = heat of sublimation - heat of vaporization
ΔH = 277 kJ/mol - 271 kJ/mol
ΔH = 6 kJ/mol
The heat required = n ΔH
= 0.500 × 6
= 3 kJ
Thus, At 1 atm pressure the heat of sublimation of gallium is 277 kJ/mol and the heat of vaporization is 271 kJ/mol. heat is required to melt 0.500 mol of gallium at 1.00 atm pressure is 3 kJ.
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