2Al₂O₃ → 4Al + 3O₂
the mass of aluminum that can be formed from Al₂O₃ is 540g.
The reaction is given as follows :
2Al₂O₃ → 4Al + 3O₂
mass of the aluminum oxide = 1020 g
molar mass of aluminum oxide = 101.96 g/mol
moles of aluminum oxide = mass / molar mass
= 1020 / 102
= 10 mol
2 mol of aluminum oxide produced 4 mol of Al
10 mol of aluminum oxide = (4/2) × 10 = 20 mol
moles of aluminum = 20 mol
molar mass of Al = 27 g/mol
mass of Aluminum = moles × molar mass
= 20 × 27
= 540 g
thus the reaction is :
2Al₂O₃ → 4Al + 3O₂
the mass of aluminum that can be formed from Al₂O₃ is 540g.
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