Question

if the pendulum is brought on the moon where the gravitational acceleration is about g/6 , approximately what will its period now be?

Answer 1

The time period of moon will be one sixth of earth.

For the time period ,

$T=2\pi \sqrt{\frac{L}{g} }$

Earth has strong gravitational force.

It is six times the influence of earth.

Therefore influence of moon will be one sixth of the influence of earth.

• For the pendulum at earth surface is

$Te= 2\pi \sqrt{\frac{Le}{ge} }$----------------------[1]

• For the pendulum at moon's surface is

$Tm= 2\pi \sqrt{\frac{Lm}{gm} }$--------------------[2]

The time period of pendulum on earth and moon will be equal that equalizes T=2  s. Equating the two equations is the utmost of the question.

Eq 1 = Eq 2

$\frac{ge}{gm}=6\\ \\\frac{ge}{6}=gm$

$Lm=\frac{Le}{6}$

To know more about gravitational force-

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