Question

a random sample of 4000 u.s. citizens yielded 2250 who are in favor of gun control legislation. estimate the true proportion of all americans who are in favor of gun control legislation using a 90% confidence interval.

Answer 1

The true proportion of all Americans who are in favor of gun control legislation using a 90% confidence interval is 0.5754.

Here is the calculation:

• P∧= 2250/4000= 0.5625
• б= 0.00784
• E= 1.645 ×0.0784= 0.0129
• p∧±E = 0.5625- 0.0129 = 0.5496 lower
• upper : 0.5625 + 0.0129 = 0.5754.
• The true proportion of all Americans who are in favor of gun control legislation using a 90% confidence interval is between 0.5496 lower -0.5754 upper.

Read more about the proportion :

https://brainly.com/question/19994681

#SPJ4