Question

for a certain art exhibit, a museum sold admission tickets to groups of 30 people every 5 minutes from 9:00 in the morning to 5:55 in the afternoon, inclusive. the price of a regular admission ticket was $10 and the price of a student ticket was $6. if on one day 3 times as many regular admission tickets were sold as student tickets, what was the total revenue from ticket sales that day?

Answer 1

Using Algebra operation,

the total revenue from ticket sales on that day is $ 3444..

We have given the following information,

timing of museum for entry is 9:00 am to 5:55pm. i.e 8 hours 55 minutes .

price of ticket for a regular admission= $10

price of ticket for a student admission = $6

30 people's admission in every 5 minutes so,

inclusive there are 9×12=108 five-minute intervals, total of tickets were sold = 108× 30

= 3240

let x student and 3x regular tickets were sold on that day.

then, x+3x= 108× 30 –> x= 3240/4 = 810

put x= 7560 in above formula, for regular admission, 3x=3× 81 = 243

So, the total revenue from ticket sales that day was 243×$10 + 810×$6 = $2430 + $4860

= $7290

Hence, total revenue from tickect sales is $7290.

To learn more about Algebra operation, visit:

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