consider a ball thrown up from the surface of the earth in the air at an angle of 30 degrees above the horizontal. air friction is negligible. just after the ball is released its acceleration is:

Respuesta :

Assuming friction =0 , the computed acceleration is 6.12736 x 10¹⁷m/s².

  • Principle:- Lets assume that ball is thrown up with an inclination of 30degrees above the normal force.
  1. Since there is field acting on all objects.
  2. Just as a point charge acts as dipole when its under influence of Electric field.
  3. Solenoid acts as magnet under the influence of Magnetic field.
  4. Earth has its shield under which Gravitational force is inevitable.
  5. Time period is 3.69 seconds.
  • Equations & Calculations:-

[tex]\lim_{n \to \330} a_n =\alpha \\[/tex]

[tex]\alpha =\left \{ {{y=2} \atop {x=2}} \right.[/tex]

[tex]Frequency= \frac{1}{3.69}=0.2710[/tex]

[tex]E=h\frac{c}{y}[/tex]

[tex]v=c/y[/tex]

[tex]y=c/v[/tex]

[tex]y=\frac{3*10^8}{0.2710}[/tex]

[tex]y=1.10701 * 10^9m[/tex]

[tex]da=ydy\\\\\int\limits^{} \, da=\int\limits^{} \, ydy------[integrating]\\\\a=\frac{y^2}{2}[/tex]

[tex]a=\frac{(1.10701*10^9)^2}{2} \\\\a=1.22547 * 10^{18}/2\\\\a=6.1273 *10^{17} m/s^{2}[/tex]

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