For the given quadratic equation, 16x² + 8x + 2 = 0 the value of x is equal to (1/4)( -1 ± i ).
As given in the question,
Given quadratic equation is equal to :
16x² + 8x + 2 = 0
Simplify the given quadratic equation to get the value of x we get,
16x² + 8x + 2 = 0
⇒ 2 ( 8x² + 4x + 1 ) = 0
⇒ 2 ≠ 0
Therefore,
8x² + 4x + 1 = 0
Simplify it using discriminant ,
x = [- 4 ± √ ( -4 )² - 4(8)(1) ]/2(8)
⇒ x = [ -4 ± √16 -32 ] / 16
⇒ x = [ -4 ± √-16 ] / 16
⇒ x = [ -4 ± 4i ] /16
⇒ x = (1/4) ( -1 ± i )
Therefore, for the given quadratic equation, 16x² + 8x + 2 = 0 the value of x is equal to (1/4)( -1 ± i ).
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