a car is driving around a skid pad on a test track, which is a circular path to test how well a car can grip the road while turning. it manages to round a 700 foot radius skid pad with a lateral (centripetal) acceleration of 1.07g (multiples of gravitational acceleration). how fast is the car going?

Respuesta :

The car is travelling on the skid pad of the test track with a speed of 47.3m/s.

The radius of the skid pad on which the car is driving is 700 foot.

The lateral centripetal acceleration of the car is 1.07g.

g is the acceleration due to gravity(gravitational acceleration)

one foot is equal to 0.3048m.

So, 700 foot is equal to 213.36m.

Relation between the radius of the track the centripetal acceleration and the speed of the car is,

a = v²/r

Where,

a is the centripetal acceleration(lateral acceleration), v is the velocity, r is the radius.

Putting values,

1.07×9.8 = v²/213.36

v = 47.3 m/s.

The car is travelling with a speed of 47.3m/s.

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