Question

The experiment described in the procedure was performed using a sample of Aluminum with HCl(aq). The lab conditions were 26. 00 °C, and 752. 0 torr barometric pressure. 95. 88 mg of Aluminum (MM: 26. 98 g/mol) was reacted with 30. 00 mL of 0. 667 M HCl(aq). 71. 560 g of water was collected when the reaction was complete, and it required 27. 83 mL of 0. 333 M NaOH(aq) to titrate the reaction mixture. Water at 26. 00 °C has a density of 0. 9965 g/cm3, and a vapor pressure of 25. 20 torr. The value for R is 0. 082058 L•atm/mol•K. What is the ratio of moles HCl(aq) that react with the metal to the moles of metal reacted?

Answer 1

mole ratio between magnesium metal and hydrochloric acid. This tells you that the reaction will always consume

What is the mole ratio of the reaction?

The balancing coefficients in reaction A show that the reactant NaHCO3 and product NaCl have a 1:1 mole ratio. This means that 1 mole of sodium chloride should be produced for every mole of sodium bicarbonate that reacts. In reaction B, however, the balancing coefficients show that the reactant Na2CO3 and product NaCl have a 1:2 mole ratio. In this case, 2 moles of sodium chloride should be produced for every mole of sodium carbonate that reacts.

Percent Yield =Experimental Yield/Theoretical Yield X 100

• (A) sodium bicarbonate + hydrochloric acid + carbon dioxide + water
• (B) sodium carbonate + hydrochloric acid + carbon dioxide + water

Simply balancing the chemical equations for these reactions would be the simplest way to obtain the mole-to-mole ratios. This is regarded as a theoretical approach to the problem. The balanced \sequations for reactions A and B are:

• 1 NaHCO3 (s) + 1 HCl (aq) 1 NaCl (aq) 1 CO2 (g) 1 H2O (l)
• (B) 2 NaCl (aq) + 1 CO2 (g) + 1 H2O = 1 Na2CO3 (s) + 2 HCl (aq) (l)

To learn more about mole ratio refer to:https://brainly.com/question/20721203

#SPJ4