The inequality that needs to be solved is:
3t +270/ 6 ≥ 90.
let we consider that Heidi has 6 subjects in her school.
Therefore, She needs to average at least 90 on her three remaining tests to have at least a 90 overall average for all 6 tests.
Now,
To obtain an average first add up all the scores of the tests and then divide by the number of tests.
So far Heidi has taken 3 tests and we know the total number of tests will be 6 so we will be dividing by 6 to get the average of all the score.
If we let each of the three remaining tests each be represent by t, then the sum of all the tests would be:
95 + 92 + 86 + t + t + t
or
273 + 3t
The average of these 6 tests can then be represented by:
3t + 273 / 6
And for her average to be at least 90 then she can get a 90 or more which is the same as ≥ 90
So the inequality that needs to be solved is:
[tex]\frac{3t + 273}{6}[/tex] ≥ 90
or, [tex]\frac{3 ( t + 91)}{6} \geq 90[/tex]
or, [tex]\frac{t + 91}{2} \geq 90[/tex]
Now, Heidi has to score :
t/2 ≥ 91
or, t/2 ≥ 90
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