Respuesta :

Answer:

3 ¹/₃ years

Step-by-step explanation:

Simple Interest Formula

I = Prt

where:

  • I = Total interest.
  • P = Principal amount.
  • r = Annual interest rate (in decimal form).
  • t = Time (in years).

Given:

  • I  = $500
  • P = $3,000
  • r = 5% = 0.05

Substitute the given values into the formula and solve for t:

[tex]\sf \implies 500=3000 \times 0.05 \times t[/tex]

[tex]\sf \implies 500=150t[/tex]

[tex]\sf \implies t=\dfrac{500}{150}[/tex]

[tex]\implies \sf t=3\frac{1}{3}[/tex]

Therefore, the money must be left in the account for 3 ¹/₃ years for the account to earn $500 interest.

GiveN:-

  • Principal = $3,000
  • Rate = 5% = 0.05
  • Interest = $500 years

To FinD:-

  • Interest = ??

SolutioN:-

[tex] \\ \diamond{\underline{\underline{\sf {\color{red}{\;Calculating \; Time \; :-}}}}} \\ [/tex]

[tex]\\ \qquad{\underline{\boxed {\bf{ Interest (I)= \: P \times R \times T}}} }\red\bigstar \\[/tex]

[tex]\\ \sf \implies \: Interest (I)= \: P \times R \times T \\[/tex]

[tex]\\ \sf \implies \: 500= \: 3000 \times 0.05 \times t \\ [/tex]

[tex]\\ \sf \implies \: 500= \: 3000 \times 0.05t \\ [/tex]

[tex]\\ \sf \implies \: 500= \: 150t \\ [/tex]

[tex]\\ \sf \implies \: 150t= \: 500\\ [/tex]

[tex]\\ \sf \implies \: t= \: \frac{500}{150} \\ [/tex]

[tex]\\ \sf \implies \: t= \: \frac{50\cancel{0}}{15\cancel{0}} \\ [/tex]

[tex]\\ \sf \implies \: t= \: \cancel{\frac{50}{15}} \\ [/tex]

[tex]\\ \sf \implies \: t= \ 3.5 \\ [/tex]

[tex]\\{\implies{\red {\underline {\boxed{ \sf { Time= \ 3.5 \: years}}}}}}\purple\bigstar \\ [/tex]

[tex] \\ \qquad{ \underline{\rule{120pt}{2pt}}} \\ [/tex]

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