The ammonium nitrate concentration in the resulting solution is 0.08 M.
The molarity and volume are related to each other by the formula -
[tex] M_{1}[/tex] [tex] V_{1}[/tex] = [tex] M_{2}[/tex] [tex] V_{2}[/tex], where values at Left Hand Side are initial concentration and volume and values are Right Hand Side are final concentration.
Keep the values in formula to find final concentration.
0.467 × 50 = [tex] M_{2}[/tex] × 290
Performing multiplication in the equation
[tex] M_{2}[/tex] = 23.35 ÷ 290
Performing division on Right and Side of the equation
[tex] M_{2}[/tex] = 0.08 M
Thus, the final molarity is 0.08 M.
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