Question

a basket holds 100 chips that are labeled with the integers 1 through 100. a chip is drawn at random from the basket, it is replaced, and a second chip is drawn at random (it might be the same chip). let x be the sum of the numbers on the two chips. what is the expected value of x?

Answer 1

The expected value of the uniform variable x is of 101.

What is the uniform probability distribution?

The uniform probability distribution is a distribution with two bounds, given by a and b, in which each possible outcome is equally as likely.

The expected value of the uniform probability distribution is given by the mean of the two bounds, as follows:

E(X) = (a + b)/2.

The chips are labeled with the integers 1 through 100, hence the bounds are given as follows:

a = 1, b = 100.

In this problem, we have two trials, each with a = 1 and b = 100, hence the expected value of x is obtained as follows:

E2(x) = 2E(X) = 2(a + b)/2 = a + b = 1 + 100 = 101.

As the mean of the two trials is calculated as the sum of the means of each trial.

More can be learned about the uniform distribution at brainly.com/question/28852504

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