Question

what total volume of ozone measured at a pressure of 29.5 mmhg and a temperature of 218 k can be destroyed when all of the chlorine from 16.5 g of cf3cl goes through 10 cycles of these reactions?

Answer 1

Total volume of Ozone measured is =  1.7527 m³

As data is provided:

Mass  of  CF₃Cl = 16.5 g

Molar mass  of  CF₃Cl  = 104.46 g/mol

Pressure ( P ) = 29.5 mmHg

T = 218 K

Gas constant ( R ) = 62.363 L mmHg/K mol

as,  Determine number of moles in each cycle reaction

n = m / M  

m = mass = 16.5 g

M = molar mass = 104.46 g/mol

∴ n = 16.5 / 104.46 = 0.1579

So, the number of moles in 10 cycle = 20 * 0.1579 = 3.1 moles

Ideal gas law to determine the volume of Ozone

PV = nRT  

n = 3.1

V = ?

R = 62.363 L mmHg/K mol

T = 218 K

P = 24.5 mmHg

∴ V = nRT / P

     = ( 3.1 * 62.363 * 218 ) / 24.5

     = 1720.72 L ≈ 1.720 m³

Hence, Total volume of Ozone measured is =  1.7527 m³

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