89. when two cotton plugs, one moistened with ammonia and the other with hydrochloric acid, are simultaneously inserted into opposite ends of a glass tube that is 87.0 cm long, a white ring of nh4cl forms where gaseous nh3 and gaseous hcl first come into contact. at approximately what distance from the ammonia-moistened plug does this occur? (hint: first calculate the ratio of diffusion rates for nh3 and hcl, and find out how much faster nh3 diffuses than hcl.)

Respuesta :

This is how far away from the ammonia-dampened plug[tex]&x=51.7 \mathrm{~cm} f r 0 \mathrm{~m} \mathrm{NH}[/tex]

How can you figure out the diffusion ratio of NH3 and HCl?

  • Diffusion and the effusion process are connected. Effusion is the process by which a confined gas escapes from its container through a very small opening.
  • An effusion is shown by the fact that a helium-filled balloon eventually stops floating and sinks to the ground. This is caused by the helium gas evaporating through the balloon's microscopic pores.
  • Both diffusion and effusion are influenced by the velocity at which different gas molecules move. Lower molar mass gases diffuse and effuse more quickly than higher molar mass gases.

Given,

molar mass of [tex]$\mathrm{HCl}=36.5$[/tex]

molar mass of [tex]$\mathrm{NH}_3=17$[/tex]

Now, Rate [tex]$\propto \frac{1}{\sqrt{\text { molar mass }}}$$[/tex]

[tex]\frac{\text { Rate of } \mathrm{NH}_3}{\text { Rate of } \mathrm{HCl}} &=\sqrt{\frac{36.5}{17}}=\sqrt{\frac{\text { molar mass of } \mathrm{HCl}}{\text { molar mass of } \mathrm{NH}_3}} \\[/tex]

[tex]&=\frac{6.04}{4.12}=\frac{1.47}{100}[/tex]

We know,

[tex]\frac{\text { Distance }}{\text { rate }}=\text { time }[/tex]

Let x = d distance travelled by[tex]$\mathrm{NH}_3$[/tex]

87 - x = distance travelled by [tex]$\mathrm{HCl}$[/tex]

[tex]&\frac{x}{1.47}=\frac{87-x}{1} \quad \text { (comparing both } \mathrm{NH}_3 \& \mathrm{HCl} \text { ) } \\[/tex]

[tex]&x=1.47(87-x) \\[/tex]

[tex]&2.47 x=127.89 \\[/tex]

[tex]&x=51.7 \mathrm{~cm} f r 0 \mathrm{~m} \mathrm{NH}[/tex] is

Hence, This is how far away from the ammonia-dampened plug[tex]&x=51.7 \mathrm{~cm} f r 0 \mathrm{~m} \mathrm{NH}[/tex]

To learn more about NH3, refer to:

https://brainly.com/question/14854495

#SPJ1

ACCESS MORE