A 145 g baseball is dropped from a tree 2 m long. The speed with which it would hit the ground will be 6.26m/s.
let's consider the height from where the ball dropped be h1 and initial velocity u and height when the ball hit the ground be h2 and the final velocity v. Initial velocity u is zero as the ball is being dropped.
So , from the conservation of energy
initial energy = final energy
1/2mu²+mgh1 = 1/2mv²+mgh2
0 + mgh1 = 1/2 mv² + 0 ( h2 is zero when ball hit the ground)
g*h1= 1/2 v²
we have to find the speed through which the ball will hit the ground -
v =√2*g*h1
v=√2*9.8*2
v=6.26m/s.
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