Question

a chemist must prepare of aqueous iron(iii) bromide working solution. he'll do this by pouring out some aqueous iron(iii) bromide stock solution into a graduated cylinder and diluting it with distilled water. calculate the volume in of the iron(iii) bromide stock solution that the chemist should pour out. be sure your answer has the correct number of significant digits.

Answer 1

The volume of the iron(iii) bromide stock solution that the chemist should pour out will be 137 ml.

Initial volume of Iron (III) Bromide (FeBr3) solution (V1) = 475 ml

Initial molarity of Iron (III) Bromide (FeBr3) solution (M1) = 1.0 M

Final molarity of Iron (III) Bromide (FeBr3) solution (M2) = 3.47 M

Final volume of Iron (III) Bromide (FeBr3) solution (V2) = ?

To find out the final volume (V2) we will use the following equation

   M1V1 = M2V2

Rearrange the equation for final volume (V2)

   V2 = M1V1 / M2

Put the values in the above equation

   V2 = 1.0 M × 475 ml / 3.47 M

   V2 = 475 / 3.47 ml

   V2 = 137 ml

The complete question is attached.

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https://brainly.com/question/16727614

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