Question

a box of mass 5 kg is at rest on a rough horizontal surface. the coefficients of static and kinetic friction between the surface and the box are 0.3 and 0.25, respectively. a 10 n horizontal force is applied to the box. what is the frictional force acting on the box?

Answer 1

The frictional force acting on the box along the rough horizontal surface is determined as 14.7 N.

What is the frictional force acting on the box?

The frictional force acting on the box is calculated by applying Newton's second law of motion as shown below.

F = μmg

where;

• μ is the coefficient static friction
• m is the mass of the box
• g is acceleration due to gravity

The given parameters;

the coefficient of static friction = 0.3

mass of the box = 5 kg

acceleration due to gravity = 9.8 m/s²

F = 0.3 x 5 x 9.8

F = 14.7 N

Learn more about frictional force here: https://brainly.com/question/4618599

#SPJ1