A company dyes two sizes of rugs. A small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing. The dyers have to make at least 20 rugs, and they must do it in less than 120 hours. Let x equal small rugs and y equal medium rugs. Which of the following inequalities can be paired with x + y ≥ 20 to create a system that represents this situation?

6x + 4y < 120
4x + 6y < 120
6x + 4y > 120
4x + 6y > 120

Given: A small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing. The dyers have to make at least 20 rugs, and they must do it in less than 120 hours.

We have write an inequalities that can be paired with x + y ≥ 20 to create a system that represents the given situation and choose the correct option from given options.

Let x represents the small rugs and y represents the medium rugs.

Also, x + y ≥ 20 represents the dyers have to make at least 20 rugs.

And it is given that a small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing and that they must do it in less than 120 hours.

So, time taken to dye x small rugs = 4x

also, time taken to dye y medium rugs = 6y

And they have maximum of 120 hours.

So this inequality is represented by 4x + 6y < 120

Thus, 4x + 6y < 120 inequalities that can be paired with x + y ≥ 20 to create a system that represents the given situation.

sophiasapp99 sophiasapp99 · Answer 2 · 2020-12-09T15:32:35+01:00

sophiasapp99 sophiasapp99

09-12-2020

Answer:

The answer is 4x + 6y < 120

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