Two semicircles are attached to the sides of a rectangle as shown.

What is the area of this figure?

Use 3.14 to approximate pi.

Enter your answer in the box. Round only your final answer to the nearest whole number.

ft²

A rectangle with a height of 18 ft and a width of 8 ft has two semi circles attached with to the wide sides with lengths of 8 ft.

Respuesta :

Answer:

[tex]194\ ft^{2}[/tex]

Step-by-step explanation:

we know that

The area of the figure is equal to the area of the rectangle plus the area of one circle (Remember that the area of two semicircles is equal to the area of one circle)

step 1

Find the area of rectangle

The area of rectangle is equal to

[tex]A=bh[/tex]

we have

[tex]b=8\ ft[/tex]

[tex]h=18\ ft[/tex]

substitute

[tex]A=8*18=144\ ft^{2}[/tex]

step 2

Find the area of one circle

The area of the circle is equal to

[tex]A=\pi r^{2}[/tex]

we have

[tex]r=8/2=4\ ft[/tex]

[tex]\pi=3.14[/tex]

substitute

[tex]A=(3.14)(4^{2})=50.24\ ft^{2}[/tex]

step 3

Find the area of the figure

[tex]144\ ft^{2}+50.24\ ft^{2}=194.24\ ft^{2}[/tex]

Round to the nearest whole number

[tex]194.24\ ft^{2}=194\ ft^{2}[/tex]

Answer: 194 ft

Step-by-step explanation:

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