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21-02-2017
Mathematics

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How many possible combination outcomes consist of two heads when you toss a fair coin four times?

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LammettHash LammettHash

22-02-2017

[tex]\dbinom42=\dfrac{4!}{2!(4-2)!}=\dfrac{4\times3\times2\times1}{2\times1\times2\times1}=3\times2=6[/tex]

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