Suppose you have a normally distributed set of data pertaining to a standardized test. The mean score is 500 and the standard deviation is 100. What is the z-score of 225 point score?

Respuesta :

[tex]z=\dfrac{225-500}{100}=-2.75[/tex]

Answer: -2.75

Step-by-step explanation:

Given : We have a normally distributed set of data pertaining to a standardized test.

The mean score is [tex]\mu=500[/tex]

Standard deviation: [tex]\sigma=100[/tex]

Let x be a random variable to represent the data values .

The formula for z-score :-

[tex]z=\dfrac{x-\mu}{\sigma}[/tex]

For x=225, we have

[tex]\Rightarrow\ z=\dfrac{225-500}{100}=-2.75[/tex]

Hence, the z-score of 225 point score =-2.75

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