Question

Solve the following linear system of equations using substitution.
Y=3x-5
Y=2x-6

Answer 1

y=3x-5
y=2x-6

Move the X's to the other side on both equations to make equations easier to solve.

-3x+y=-5
-2x+y=-6

Subtract equations.

-x=1
x=-1

y=3x-5

y=3(-1) -5

y=-3-5
y=-8

~Hope I helped!~

Answer 2

Answer:

The required value of $x$ and $y$ are -8 and -1 respectively.

Step-by-step explanation:

Given information

Equation number (1)  $y=3x-5$  

Equation number (2) $y=2x-6$

Now , according to the substitution method of solving linear equation,

we need to find the value of $x$ from equation (1) and substitute in equation (2).

so, from equation (1)

$y=3x-5\\3x=y+5\\x=(y+5)/3$

Now, substitute the value of $x$ in equation (2)

$y=2x-6\\y=2((y+5)/3)-6$

$y=((2y+10)/3)-6\\3y=2y+10-18$

$3y-2y=10-18$

on solving the above equation we get the value of $y$ as:

$y=-8$

Now, substitute the value of $y$ in equation (1) to get the value of $x$

$y=3x-5\\-8=3x-5\\3x=-8+5\\3x=-3\\x=-3/3$

on solving the above equation we get the value of $x$ as:

$x=-1$

Hence, the required value of $x$ and $y$ are -8 and -1 respectively.

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