Question

2x(squared) + 23x-19=0

Answer 1

use quadratic formula

for ax^2+bx+c=0
x=$\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
2x^2+23x-19=0
a=2
b=23
c=-19

x=$\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}$
x=$\frac{-23+/- \sqrt{529-152} }{4}$
x=$\frac{-23+/- \sqrt{377} }{4}$

x=$\frac{-23+ \sqrt{377} }{4}$ or $\frac{-23- \sqrt{377} }{4}$