Question

Given the following probability distribution for the random variable X, what is the probability of the random variable X being at least seven?X-valueP(X)-60.3170.2380.1190.26100.09Write your answer as a decimal.

Answer 1

Given

The probability distribution for the random variable X is,

X - 6 7 8 9 10

P(X) - 0.31 0.23 0.11 0.26 0.09

To find the probability of the random variable X being at least seven.

Explanation:

It is given that,

The probability distribution for the random variable X is,

X - 6 7 8 9 10

P(X) - 0.31 0.23 0.11 0.26 0.09

Then,

$\begin{gathered} P(at\text{ }least\text{ }7)=P(X=7)+P(X=8)+P(X=9)+P(X=10) \\ =1-P(6) \\ =1-0.31 \\ =0.69 \end{gathered}$

Hence, the probability of the random variable X being at least seven is 0.69.