Question

A 15.5 L balloon contains helium gas at a pressure of 840 mmHg. What is the final pressure, in millimeters of mercury, if the final volume is 9.25 L?

Answer 1

Answer

The final pressure is 1407.56 mmHg

Explanation

Given:

Initial volume, V₁ = 15.5 L

Initial pressure, P₁ = 840 mmHg = 1.10526 atm

Final volume, V₂ = 9.25 L

What to find:

The final pressure, in mmHg.

Step-by-step solution:

The final pressure, P₂ can be calculated using Boyle's law formula.

$\begin{gathered} P_1V_1=P_2V_2 \\ \\ \Rightarrow P_2=\frac{P_1V_1}{V_2} \end{gathered}$

Putting the values of the given parameters into the formula, we have;

$\begin{gathered} P_2=\frac{1.10526\text{ }atm\times15.5\text{ }L}{9.25\text{ }L}=1.852057297\text{ }atm \\ \\ In\text{ }mmHg; \\ \\ P_2=1.852057297\times760\text{ }mmHg=1407.56\text{ }mmHg \end{gathered}$

The final pressure is 1407.56 mmHg