Answer:
b. 8
Explanation:
Let the length of the rectangle = l units
The width is 5 units less than the length. Therefore:
• The width of the rectangle = (l-5) units
[tex]\begin{gathered} \text{Area of a Rectangle}=\text{Length}\times Width \\ \implies24=l(l-5) \end{gathered}[/tex]We solve the resulting equation for l.
[tex]\begin{gathered} l^2-5l=24 \\ l^2-5l-24=0 \\ l^2-8l+3l-24=0 \\ l^{}(l-8)+3(l-8)=0 \\ (l+3)(l-8)=0 \\ l+3=0\text{ or }l-8=0 \\ l=-3\text{ or }l=8 \end{gathered}[/tex]Since length cannot be negative, the length of the rectangle is 8 units.