Question

Question 4 If the vertices of ABC are A(-3,5), B(2,4). and C(-1,2), then ABC is classified as

Answer 1

To be able to classify the triangle you have to plot it

You can calculate the length of the sides as follows:

$\begin{gathered} AC=\sqrt[]{(-1+3)^2+(5-2)^2} \\ AC=\sqrt[]{13} \end{gathered}$$\begin{gathered} AB=\sqrt[]{(5-4)^2+(2+3)^2} \\ AB=\sqrt[]{26} \end{gathered}$$\begin{gathered} BC=\sqrt[]{(2+1)^2+(4-2)^2} \\ BC=\sqrt[]{13} \end{gathered}$

Sides AC and BC are equal.

You can classify this triangle as an isosceles triangle