What is the area, in square feet, of the trapezoid below?8.8 ft4 ft5-3 ft
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We are asked to find the area of the trapezoid.
Recall that the area of the trapezoid is given by
[tex]A=\frac{1}{2}(b_1+b_2)\times h[/tex]Where b₁ is the length of base 1 that is 8.8 ft
b₂ is the length of base 2 that is 5.3 ft
h is the height that is 4 ft
Let us substitute the given values into the above formula
[tex]\begin{gathered} A=\frac{1}{2}(8.8+5.3)\times4 \\ A=\frac{1}{2}(14.1)\times4 \\ A=\frac{1}{2}(56.4)_{} \\ A=28.2ft^2 \end{gathered}[/tex]Therefore, the area of the trapezoid is 28.2 ft²