From the graph, the vertical intercept is 120°F
The slope, m, of the line that passes through the points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_!}[/tex]From the graph, the line passes through the points (0, 120) and (55, 60), then its slope is:
[tex]m=\frac{60-120}{55-0}=-\frac{12}{11}[/tex]The slope-intercept form of a line is:
y = mx + b
where m is the slope and b is the y-intercept. In this case, the equation is
y = -12/11x + 120
Substituting with y = 0, we get:
[tex]\begin{gathered} 0=-\frac{12}{11}x+120 \\ -120=-\frac{12}{11}x \\ (-120)\cdot(-\frac{11}{12})=x \\ 110=x \end{gathered}[/tex]The horizontal intercept is 110°N