Question

A bag contains 6 apples and 4 bananas. If two fruits are drawn one by one with replacement, find the probability that the first one is an apple and the second one is banana.

Answer 1

we have

probability first one is an apple:

$\frac{6}{6+4}=\frac{6}{10}$

probability the second one is banana:

$\frac{4}{6+4}=\frac{4}{10}$

therefore, the probability that the first one is an apple and the second one is banana:

$\frac{6}{10}\times\frac{4}{10}=\frac{24}{100}=\frac{6}{25}$

answer: 6/25