Question

determine the numbers of solutions that exist to the equation below 8 (j - 4) = 2(4j - 16)

Answer 1

Step 1: Write out the equation

$8(j-4)=2(4j-16)$

Step 2: Divide both sides by 2

$\begin{gathered} \frac{8(j-4)}{2}=\frac{2(4j-16)}{2} \\ \text{Therefore} \\ 4(j-4)=4j-16 \end{gathered}$

Step 3: Expand the left side of the equation to get

$\begin{gathered} 4j-16=4j-16 \\ \text{Thus} \\ 4j-4j=-16+16 \\ 0=0 \end{gathered}$

0 = 0 is always true no matter the value of j.

Hence, the number of solutions is infinite