Question

Triangle ABC shown below has m B = 38°, a = 8, and c = 16. Find the area of the triangle. Round your answer to the nearest tenth and do not include units in your answer.

Answer 1

The area of triangle is determined as

$A=\frac{1}{2}a\times c\times\sin B$$A=\frac{1}{2}\times8\times16\times\sin 38=64\sin 38^{\circ}$$A=39.4\text{ squnit}$

Thus the area of triangle is 39.4 sq.unit.